37x+15=-20x^2

Solution for 37x+15=-20x^2 equation:

37x+15=-20x^2

We move all terms to the left:

37x+15-(-20x^2)=0

We get rid of parentheses

20x^2+37x+15=0

a = 20; b = 37; c = +15;
Δ = b2-4ac
Δ = 372-4·20·15
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-13}{2*20}=\frac{-50}{40}
=-1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+13}{2*20}=\frac{-24}{40}
=-3/5
$